Question:

Ba, Ca, Sr form halide hydrates. Their formulae are \( BaCl_2 \cdot xH_2O \), \( CaCl_2 \cdot yH_2O \), \( SrCl_2 \cdot zH_2O \). The values of \( x, y, z \) respectively are:

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Hydration numbers of alkaline earth metal chlorides depend on their size and charge density. BaCl\(_2\) forms a dihydrate, whereas CaCl\(_2\) and SrCl\(_2\) form hexahydrates.
Updated On: Mar 25, 2025
  • \( 2, 6, 6 \)
  • \( 8, 6, 4 \)
  • \( 8, 6, 6 \)
  • \( 6, 4, 2 \)
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The Correct Option is A

Solution and Explanation

The question states that Barium (Ba), Calcium (Ca), and Strontium (Sr) form halide hydrates with the formulas \(BaCl_2 \cdot xH_2O\), \(CaCl_2 \cdot yH_2O\), and \(SrCl_2 \cdot zH_2O\). It asks for the values of x, y, and z.

The common halide hydrates formed by these alkaline earth metals are:

  • \(BaCl_2 \cdot 2H_2O\) (Barium chloride dihydrate)
  • \(CaCl_2 \cdot 6H_2O\) (Calcium chloride hexahydrate)
  • \(SrCl_2 \cdot 6H_2O\) (Strontium chloride hexahydrate)

Therefore, x = 2, y = 6, and z = 6.

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