Question

The complete hydrolysis of $ \text{ICl} $, $ \text{ClF}_3 $, and $ \text{BrF}_5 $, respectively, gives

• A. \( \text{IO}^-, \text{ClO}_2^- \) and \( \text{BrO}_3^- \)
• B. \( \text{IO}_3^-, \text{ClO}_2^- \) and \( \text{BrO}_3^- \)
• C. \( \text{IO}^-, \text{ClO}^- \) and \( \text{BrO}_2^- \)
• D. \( \text{IO}_3^-, \text{ClO}_4^- \) and \( \text{BrO}_2^- \)

Hint:

In hydrolysis of halogen fluorides and interhalogen compounds, look at the central atom's oxidation state to predict the oxyanion formed.

Answer 1

The Correct Option is B

Let’s examine the hydrolysis reactions one by one: - Hydrolysis of ICl: ICl is a halogen interhalide. On hydrolysis, it forms iodic acid which further ionizes to give iodate ion: \[ \text{ICl} + \text{H}_2\text{O} \rightarrow \text{HIO}_3 + \text{HCl} \Rightarrow \text{IO}_3^- \] - Hydrolysis of ClF\(_3\): Chlorine trifluoride undergoes hydrolysis to give chlorine dioxide: \[ \text{ClF}_3 + \text{H}_2\text{O} \rightarrow \text{ClO}_2 + \text{HF} \Rightarrow \text{ClO}_2^- \] - Hydrolysis of BrF\(_5\): Bromine pentafluoride gives bromic acid on hydrolysis: \[ \text{BrF}_5 + \text{H}_2\text{O} \rightarrow \text{HBrO}_3 + \text{HF} \Rightarrow \text{BrO}_3^- \] Hence, the correct combination of products is \( \text{IO}_3^- \), \( \text{ClO}_2^- \), and \( \text{BrO}_3^- \).