Step 1: Use the formula for latus rectum.
For an ellipse, the length of the latus rectum is \( \dfrac{2b^2}{a} \), and eccentricity is \( e = \dfrac{c}{a} \). We're told the latus rectum is 4 and \( e = \frac{1}{2} \), so:
Let \( a \) be semi-major axis.
Since \( e = \frac{1}{2} \), we know that:
\[
b^2 = a^2(1 - e^2) = a^2 \left(1 - \frac{1}{4}\right) = \frac{3a^2}{4}
\]
\[
\text{Latus rectum} = \frac{2b^2}{a} = \frac{2 . \frac{3a^2}{4}}{a} = \frac{3a}{2}
\]
Set this equal to 4:
\[
\frac{3a}{2} = 4 \Rightarrow a = \frac{8}{3}
\]
Step 2: Validate the perpendicular formula (R).
The perpendicular from the focus to its corresponding directrix is given by:
\[
\text{Distance} = \frac{a(1 - e^2)}{e}
\]
This matches the given Reason (R), which is correct.
Step 3: Explanation correctness.
Since the directrix and focus are given, we can compute the perpendicular distance and verify the eccentricity as \( \frac{1}{2} \). Thus, both statements are true and (R) correctly explains (A).