The time period of a pendulum increases as g decreases. At higher altitudes, pendulums run slower, not faster.
The time period of a pendulum is given by:
\[ T \propto \sqrt{\frac{1}{g}} \]
At Mount Everest, \( g \) is less than on Earth’s surface. A decrease in \( g \) increases \( T \), making the pendulum slower, not faster. Thus:
T∝\(\frac {1}{\sqrt g}\)
Time period of pendulum is inversely proportional to acceleration due to gravity.
So, the correct answer is (C): A is not correct but R is correct
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].