The time period of a pendulum increases as g decreases. At higher altitudes, pendulums run slower, not faster.
The time period of a pendulum is given by:
\[ T \propto \sqrt{\frac{1}{g}} \]
At Mount Everest, \( g \) is less than on Earth’s surface. A decrease in \( g \) increases \( T \), making the pendulum slower, not faster. Thus:
T∝\(\frac {1}{\sqrt g}\)
Time period of pendulum is inversely proportional to acceleration due to gravity.
So, the correct answer is (C): A is not correct but R is correct
If $10 \sin^4 \theta + 15 \cos^4 \theta = 6$, then the value of $\frac{27 \csc^6 \theta + 8 \sec^6 \theta}{16 \sec^8 \theta}$ is:
A point particle of charge \( Q \) is located at \( P \) along the axis of an electric dipole 1 at a distance \( r \) as shown in the figure. The point \( P \) is also on the equatorial plane of a second electric dipole 2 at a distance \( r \). The dipoles are made of opposite charge \( q \) separated by a distance \( 2a \). For the charge particle at \( P \) not to experience any net force, which of the following correctly describes the situation?



In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].