





Step 1: Understanding Aspartame
Aspartame is a dipeptide formed by the condensation of aspartic acid and phenylalanine. The methyl ester group is added to the carboxyl group of the phenylalanine residue.
Step 2: Structural Features of Aspartame
Step 3: Verifying the Structure
Structure (B) correctly shows the peptide bond between aspartic acid and phenylalanine, with the methyl ester group on phenylalanine.
Conclusion
The correct structure of aspartame is represented by option (B).
To solve the problem, we need to determine the correct structure of aspartame, which is a dipeptide consisting of aspartyl phenylalanine methyl ester.
1. Understanding the Components:
Aspartame is made from aspartic acid and phenylalanine, with the phenylalanine part esterified as a methyl ester.
- Aspartic acid has two carboxyl groups, one of which forms a peptide bond.
- Phenylalanine contains a phenyl (Ph) group attached to the alpha carbon.
2. Structure of Aspartame:
- The amino group of phenylalanine bonds with the carboxyl group of aspartic acid.
- The free carboxyl group of phenylalanine is converted to methyl ester (–COOCH₃).
- The resulting structure is a dipeptide: aspartyl-phenylalanine methyl ester.
3. Identifying the Correct Option:
Among the given options, option (B) correctly shows:
- Aspartic acid with free amino and carboxyl groups.
- Phenylalanine linked via peptide bond.
- Methyl ester group at the carboxyl terminal of phenylalanine.
Thus, option (B) is the correct structure of aspartame.
Final Answer:
Option (B)
Fat soluble vitamins are :
A. Vitamin B\( _1 \)
B. Vitamin C
C. Vitamin E
D. Vitamin B\( _{12} \)
E. Vitamin K
Choose the correct answer from the options given below :
The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hooke’s law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity): 
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.