To determine the total number of hydrogen bonds in a DNA-double helix strand based on the given sequence, we must consider how base pairing occurs. In DNA, the bases Guanine (G) and Cytosine (C) pair together with 3 hydrogen bonds, while Adenine (A) and Thymine (T) pair with 2 hydrogen bonds.
The provided sequence is:
5′-G-G-C-A-A-A-T-C-G-G-C-T-A-3′
Let's count the hydrogen bonds for each base pair:
Adding all these together gives the total number of hydrogen bonds: 6 + 3 + 6 + 2 + 3 + 6 + 3 + 2 + 2 = 33.
Thus, the total number of hydrogen bonds is 33, which falls within the specified range (33,33).
To determine the total number of hydrogen bonds in a DNA double-helix strand, we need to understand the base pairing rules of DNA:
Given the DNA sequence:
5'-G-G-C-A-A-A-T-C-G-G-C-T-A-3'
Let's pair each base with its complementary base on the opposite strand and count the hydrogen bonds:
| Base Pair | Hydrogen Bonds |
| G - C | 3 |
| G - C | 3 |
| C - G | 3 |
| A - T | 2 |
| A - T | 2 |
| A - T | 2 |
| T - A | 2 |
| C - G | 3 |
| G - C | 3 |
| G - C | 3 |
| C - G | 3 |
| T - A | 2 |
| A - T | 2 |
Now, sum the total number of hydrogen bonds:
Total hydrogen bonds = 3 + 3 + 3 + 2 + 2 + 2 + 2 + 3 + 3 + 3 + 3 + 2 + 2 = 33
The total number of hydrogen bonds is 33, which is within the expected range of 33 to 33.
In the given pentapeptide, find out an essential amino acid (\(Y\)) and the sequence present in the pentapeptide. 
Choose the correct answer from the options given below:
Given below are two statements for the following reaction sequence: 
Match List-I with List-II. 
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 