Fat-soluble vitamins are vitamins that dissolve in fats and oils and can be stored in the body's fatty tissues and liver.
The fat-soluble vitamins are Vitamin A, Vitamin D, Vitamin E, and Vitamin K.
Looking at the options provided in the question: A. Vitamin B\( _1 \) (Thiamine) is a water-soluble vitamin. B.
Vitamin C (Ascorbic acid) is a water-soluble vitamin. C.
Vitamin E (Tocopherol) is a fat-soluble vitamin. D. Vitamin B\( _{12} \) (Cobalamin) is a water-soluble vitamin. E.
Vitamin K (Phylloquinone) is a fat-soluble vitamin.
Therefore, the fat-soluble vitamins from the given list are Vitamin E (C) and Vitamin K (E).
The correct answer is the option that includes only C and E.
Let \[ I(x) = \int \frac{dx}{(x-11)^{\frac{11}{13}} (x+15)^{\frac{15}{13}}} \] If \[ I(37) - I(24) = \frac{1}{4} \left( b^{\frac{1}{13}} - c^{\frac{1}{13}} \right) \] where \( b, c \in \mathbb{N} \), then \[ 3(b + c) \] is equal to:
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).