Arrange the following compounds as asked:
(a) In increasing order of pKb values: \( \text{C}_2\text{H}_5\text{NH}_2 \), \( (\text{C}_2\text{H}_5)_2\text{NH} \), \( \text{C}_6\text{H}_5\text{NHCH}_3 \), \( \text{C}_6\text{H}_5\text{NH}_2 \)
(b) In decreasing order of boiling point: \( \text{C}_2\text{H}_5\text{OH} \), \( \text{C}_2\text{H}_5\text{NH}_2 \), \( (\text{CH}_3)_2\text{NH} \)
(c) In decreasing order of solubility in water: \( \text{C}_6\text{H}_5\text{NH}_2 \), \( (\text{C}_2\text{H}_5)_2\text{NH} \), \( \text{C}_2\text{H}_5\text{NH}_2 \)
(a) In increasing order of pKb values: \( \text{C}_2\text{H}_5\text{NH}_2 \), \( (\text{C}_2\text{H}_5)_2\text{NH} \), \( \text{C}_6\text{H}_5\text{NHCH}_3 \), \( \text{C}_6\text{H}_5\text{NH}_2 \)
Solution:
Lower pKb implies stronger base. Order of increasing pKb (i.e., decreasing basicity):
\( (\text{C}_2\text{H}_5)_2\text{NH} < \text{C}_2\text{H}_5\text{NH}_2 < \text{C}_6\text{H}_5\text{NHCH}_3 < \text{C}_6\text{H}_5\text{NH}_2 \)
Quick Tip:
Aromatic amines are weaker bases due to resonance; aliphatic amines are stronger.
(b) In decreasing order of boiling point: \( \text{C}_2\text{H}_5\text{OH} \), \( \text{C}_2\text{H}_5\text{NH}_2 \), \( (\text{CH}_3)_2\text{NH} \)
Solution:
Boiling point depends on hydrogen bonding and molecular weight. Order:
\( \text{C}_2\text{H}_5\text{OH} > \text{C}_2\text{H}_5\text{NH}_2 > (\text{CH}_3)_2\text{NH} \)
Quick Tip:
Alcohols have stronger H-bonding than amines, leading to higher boiling points.
(c) In decreasing order of solubility in water: \( \text{C}_6\text{H}_5\text{NH}_2 \), \( (\text{C}_2\text{H}_5)_2\text{NH} \), \( \text{C}_2\text{H}_5\text{NH}_2 \)
Solution:
Solubility depends on ability to form H-bonds and size of hydrophobic group. Order:
\( \text{C}_2\text{H}_5\text{NH}_2 > (\text{C}_2\text{H}_5)_2\text{NH} > \text{C}_6\text{H}_5\text{NH}_2 \)
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
A hydrocarbon which does not belong to the same homologous series of carbon compounds is
Time (Hours) | [A] (M) |
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0 | 0.40 |
1 | 0.20 |
2 | 0.10 |
3 | 0.05 |