The magnetic force (\( \vec{F}_m \)) experienced by a charged particle with charge (\( q \)) moving with velocity (\( \vec{v} \)) in a magnetic field (\( \vec{B} \)) is given by:
\[ \vec{F}_m = q (\vec{v} \times \vec{B}). \]
Inside a solenoid, the magnetic field (\( \vec{B} \)) is uniform and directed along the axis of the solenoid.
Thus, the magnetic force on the electron is:
\[ \vec{F}_m = 0. \]
Since the magnetic force on the electron is zero, there is no net force acting perpendicular to its motion. As a result:
The electron will not experience a magnetic force (B), and it will continue to move along the axis of the solenoid (C).
Let $ f(x) = \begin{cases} (1+ax)^{1/x} & , x<0 \\1+b & , x = 0 \\\frac{(x+4)^{1/2} - 2}{(x+c)^{1/3} - 2} & , x>0 \end{cases} $ be continuous at x = 0. Then $ e^a bc $ is equal to
Total number of nucleophiles from the following is: \(\text{NH}_3, PhSH, (H_3C_2S)_2, H_2C = CH_2, OH−, H_3O+, (CH_3)_2CO, NCH_3\)