The torque \(\tau\) is given by:
\[ \tau = pE \sin \theta \] This can be written as: \[ \tau = (2aq) E \sin \theta \] Substituting the known values: \[ \tau = \left(5 \times 10^{-3} \times 1 \times 10^{-12} \times 10^3\right) \times \frac{4}{5} \] Simplifying: \[ \tau = 4 \times 10^{-12} \, \text{Nm} \] The direction of the torque is along the negative \(Z\)-direction.
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.