The torque \(\tau\) is given by: 
\[ \tau = pE \sin \theta \] This can be written as: \[ \tau = (2aq) E \sin \theta \] Substituting the known values: \[ \tau = \left(5 \times 10^{-3} \times 1 \times 10^{-12} \times 10^3\right) \times \frac{4}{5} \] Simplifying: \[ \tau = 4 \times 10^{-12} \, \text{Nm} \] The direction of the torque is along the negative \(Z\)-direction.


A ladder of fixed length \( h \) is to be placed along the wall such that it is free to move along the height of the wall.
Based upon the above information, answer the following questions:
(iii) (b) If the foot of the ladder, whose length is 5 m, is being pulled towards the wall such that the rate of decrease of distance \( y \) is \( 2 \, \text{m/s} \), then at what rate is the height on the wall \( x \) increasing when the foot of the ladder is 3 m away from the wall?