An aromatic compound ‘A’ with molecular formula C8H8O gives positive 2,4-DNP test. It gives yellow precipitate of compound ‘B’ on treatment with sodium hypoiodite. Compound ‘A’ does not react with Tollen’s or Fehling’s reagent; on drastic oxidation with KMnO4 it forms a carboxylic acid ‘C’. Elucidate the structures of A, B, and C. Also give their IUPAC names.
Compound A: Compound A is an aromatic ketone, phenyl methyl ketone (acetophenone), as it gives a positive 2,4-DNP test and does not respond to Tollen’s or Fehling’s reagents.
IUPAC Name: 1-phenylethanone
Compound B: Compound B is benzene with a carboxylic acid group (benzoic acid), formed on oxidation of acetophenone. Compound A reacts with NaOI (iodoform test) to form compound B, which is a yellow precipitate of iodoform. This confirms the methyl ketone group.
IUPAC Name: triiodomethane (Iodoform)
Compound C: Compound C is benzoic acid, formed upon drastic oxidation of acetophenone with KMnO4.
IUPAC Name: benzenecarboxylic acid
(i) \( \text{CH}_3\text{CH} = \text{CH}_2 \)
\( \xrightarrow{\text{HBr, Peroxide}} \) ‘A’ \( \xrightarrow{\text{aq. KOH}} \) ‘B’
(ii) \( \text{CH}_3\text{CH}_2\text{CH(Cl)CH}_3 \)
\( \xrightarrow{\text{alc. KOH}, \Delta} \) ‘A’ \( \xrightarrow{\text{HBr}} \) ‘B’
(iii) ‘A’ \( \xrightarrow{\text{Mg}} \) \( \text{CH}_3\text{CH}_2\text{CH}_2\text{MgCl} \) \( \xrightarrow{\text{H}_2\text{O, H}^+} \) ‘B’ (Main product)
Time (Hours) | [A] (M) |
---|---|
0 | 0.40 |
1 | 0.20 |
2 | 0.10 |
3 | 0.05 |