A transistor is used in an amplifier circuit in common emitter mode. If the base current changes by 100μA, it brings a change of 10mA in collector current. If the load resistance is 2kΩ and input resistance is 1kΩ, the value of power gain is \(x×10^4\). The value of x is _______.
Correct Answer: 2
Solution and Explanation
The correct answer is: 2
Power gain
\(=[\frac{\triangle{ic}}{\triangle{iB}}]×\frac{R_0}{R_i}\)
\(=[\frac{10^{-2}}{10^{-4}}]×\frac{2}{1}\)
= 2 × 104
\(⇒ x = 2\)
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Concepts Used:
Amperes circuital law
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Ampere’s circuital law can be written as the line integral of the magnetic field surrounding the closed loop which is equal to the number of times the algebraic sum of currents passing through the loop.
According to the second equation, if the magnetic field is integrated along the blue path, then it is equal to the current enclosed, I.
The magnetic field doesn’t vary at a distance r because of symmetry. The path length (in blue) in figure 1 has to be equal to the circumference of a circle,2πr.
