The formation of Prussian blue is a qualitative test for the presence of ferric ions (Fe3+) in solution
The Prussian blue precipitate is formed when ferric ions (\( \text{Fe}^{3+} \)) react with hexacyanoferrate (\( [\text{Fe(CN)}_6]^{4-} \)) ions. The product of this reaction is \( \text{Fe}_4[\text{Fe(CN)}_6]_3 \), which is an insoluble complex that imparts the characteristic deep blue color.
Step 1: Ferric chloride (\( \text{FeCl}_3 \)) dissociates to produce \( \text{Fe}^{3+} \) ions in solution.
Step 2: Potassium hexacyanoferrate (\( \text{K}_4[\text{Fe(CN)}_6] \)) dissociates to produce \( [\text{Fe(CN)}_6]^{4-} \) ions in solution.
Step 3: \( \text{Fe}^{3+} \) ions combine with \( [\text{Fe(CN)}_6]^{4-} \) to form the insoluble complex \( \text{Fe}_4[\text{Fe(CN)}_6]_3 \), known as Prussian blue.
\( 4\text{Fe}^{3+} + 3[\text{Fe(CN)}_6]^{4-} \rightarrow \text{Fe}_4[\text{Fe(CN)}_6]_3 \downarrow \) (Prussian blue precipitate)
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).

A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
The solutions can be classified into three types:
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types: