A solid spherical ball is rolling on a frictionless horizontal plane surface about its axis of symmetry. The ratio of rotational kinetic energy of the ball to its total kinetic energy is –
\(\frac{2}{5}\)
\(\frac{2}{7}\)
\(\frac{1}{5}\)
\(\frac{7}{10}\)
The Correct Option is B
Solution and Explanation
The correct answer is (B): \(\frac{2}{7}\)
KER = \(\frac{1}{2}\) lω²
= \(\frac{1}{2}\) × \(\frac{2}{5}\) x ω² × (mR²)
KEtotal = \(\frac{1}{2}\) x \(\frac{7}{5}\) x mR² x ω²
∴\(\frac{KE_R}{KE_{total}}\) = \(\frac{2}{7}\)
Top Questions on Kinetic Energy
- If a solid sphere is rolling without slipping on a horizontal plane, then the ratio of its rotational and total kinetic energies is
- AP EAPCET - 2025
- Physics
- Kinetic Energy
- A body moves in a circular path with constant speed. Its kinetic energy:
- CUET (UG) - 2025
- Physics
- Kinetic Energy
- A particle of mass 2 kg moves at 3 m/s. Its kinetic energy is:
- CUET (UG) - 2025
- Physics
- Kinetic Energy
- A body of mass 4 kg is moving with a velocity of 3 m/s. What is its kinetic energy?
- AP EAPCET - 2025
- Physics
- Kinetic Energy
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?
- JEE Main - 2025
- Physics
- Kinetic Energy
Questions Asked in JEE Main exam
- A force of 49 N acts tangentially at the highest point of a sphere (solid of mass 20 kg) kept on a rough horizontal plane. If the sphere rolls without slipping, then the acceleration of the center of the sphere is:
- JEE Main - 2025
- Quantum Mechanics
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
- JEE Main - 2025
- Relations and functions
- If \( \alpha + i\beta \) and \( \gamma + i\delta \) are the roots of the equation \( x^2 - (3-2i)x - (2i-2) = 0 \), \( i = \sqrt{-1} \), then \( \alpha\gamma + \beta\delta \) is equal to:
- JEE Main - 2025
- Complex numbers
- The sum of all local minimum values of the function \( f(x) \) as defined below is:
\[ f(x) = \begin{cases} 1 - 2x & \text{if } x < -1, \\[10pt] \frac{1}{3}(7 + 2|x|) & \text{if } -1 \leq x \leq 2, \\[10pt] \frac{11}{18}(x-4)(x-5) & \text{if } x > 2. \end{cases} \]- JEE Main - 2025
- Functions
- Let \( \langle a_n \rangle \) be a sequence such that \( a_0 = 0 \), \( a_1 = \frac{1}{2} \), and \( 2a_{n+2} = 5a_{n+1} - 3a_n \).n= 0,1,2,3.... Then \( \sum_{k=1}^{100} a_k \) is equal to:
- JEE Main - 2025
- Sequences and Series
Concepts Used:
Kinetic energy
Kinetic energy of an object is the measure of the work it does as a result of its motion. Kinetic energy is the type of energy that an object or particle has as a result of its movement. When an object is subjected to a net force, it accelerates and gains kinetic energy as a result. Kinetic energy is a property of a moving object or particle defined by both its mass and its velocity. Any combination of motions is possible, including translation (moving along a route from one spot to another), rotation around an axis, vibration, and any combination of motions.
