The quality factor (\( Q \)) of a series RLC circuit is given by: \[ Q = \frac{1}{R} \sqrt{\frac{L}{C}}, \] where:
\( R = 100 \, \Omega \),
\( L = 1 \, \text{H} \),
\( C = 6.25 \, \mu\text{F} = 6.25 \times 10^{-6} \, \text{F} \).
Substitute the values: \[ Q = \frac{1}{100} \sqrt{\frac{1}{6.25 \times 10^{-6}}}. \]
Simplify: \[ Q = \frac{1}{100} \sqrt{1.6 \times 10^5} = \frac{1}{100} \cdot 400 = 4. \]
Final Answer: The quality factor is: \[ \boxed{4}. \]
A wire of resistance $ R $ is bent into a triangular pyramid as shown in the figure, with each segment having the same length. The resistance between points $ A $ and $ B $ is $ \frac{R}{n} $. The value of $ n $ is:
0.01 mole of an organic compound (X) containing 10% hydrogen, on complete combustion, produced 0.9 g H₂O. Molar mass of (X) is ___________g mol\(^{-1}\).
If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to: