Question

A resistor of resistance $ 10\, \Omega $ is connected across a $ 20\, V $ battery. Calculate the current flowing through the resistor.

• A. \(1\, A\)
• B. \(2\, A\)
• C. \(0.5\, A\)
• D. \(4\, A\)

Hint:

Tip: Always check units and apply Ohm’s law correctly.

Answer 1

The Correct Option is B

To find the current flowing through the resistor, we use Ohm's Law, which is stated as:

Ohm's Law: V = IR

where:

• V is the voltage across the resistor (in volts)
• I is the current flowing through the resistor (in amperes)
• R is the resistance of the resistor (in ohms)

We need to find I. Rearrange Ohm's Law to solve for I:

\( I = \frac{V}{R} \)

Given:

• \( V = 20\,V \)
• \( R = 10\,\Omega \)

Substitute the given values into the formula:

\( I = \frac{20\,V}{10\,\Omega} \)

Calculate the current:

\( I = 2\,A \)

Thus, the current flowing through the resistor is 2 amperes.

Answer 2

Step 1: Recall Ohm’s Law 
\[ V = IR \] where \(V\) is voltage, \(I\) is current, and \(R\) is resistance.

Step 2: Rearrange to find current 
\[ I = \frac{V}{R} \]

Step 3: Substitute given values 
\[ I = \frac{20\, V}{10\, \Omega} = 2\, A \]