The reagent that gives a brilliant red precipitate with Nickel ions (\( \text{Ni}^{2+} \)) in a basic medium is dimethyl glyoxime (dmg). When \( \text{Ni}^{2+} \) reacts with dimethyl glyoxime, it forms a complex that produces a bright red precipitate. The reaction is as follows:
\(\text{Ni}^{2+} + \text{dmg} \rightarrow [\text{Ni}(\text{dmg})_2] \, \, (\text{Rosy red/Bright Red precipitate})\)
Thus, the correct answer is dimethyl glyoxime.
The Correct Answer is: dimethyl glyoxime
Among the following cations, the number of cations which will give characteristic precipitate in their identification tests with
\(K_4\)[Fe(CN)\(_6\)] is : \[ {Cu}^{2+}, \, {Fe}^{3+}, \, {Ba}^{2+}, \, {Ca}^{2+}, \, {NH}_4^+, \, {Mg}^{2+}, \, {Zn}^{2+} \]
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32