Question:

A random variable X has the following probability distribution:
$X$ 0 1 2
$P(X)$ $\frac{25}{36}$ k $\frac{1}{36}$
If the mean of the random variable X is $\frac{1}{3}$ , then the variance is

KCET

Updated On: May 29, 2024

$\frac{1}{18}$
$\frac{5}{18}$
$\frac{7}{18}$
$\frac{11}{18}$

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The Correct Option is B

Solution and Explanation

The correct answer is Option (B) :

\frac{5}{18}

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