Question:

A random variable X has the following probability distribution:
\(X\) 0 1 2
\(P(X)\) \(\frac{25}{36}\) k \(\frac{1}{36}\)
If the mean of the random variable X is \(\frac{1}{3}\), then the variance is

KCET

Updated On: May 29, 2024

\(\frac{1}{18}\)
\(\frac{5}{18}\)
\(\frac{7}{18}\)
\(\frac{11}{18}\)

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The Correct Option is B

Solution and Explanation

The correct answer is Option (B) : \(\frac{5}{18}\)

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