Question:
A random variable X has the following probability distribution:\(X\) 0 1 2 \(P(X)\) \(\frac{25}{36}\) k \(\frac{1}{36}\)
If the mean of the random variable X is \(\frac{1}{3}\), then the variance is
A random variable X has the following probability distribution:
| \(X\) | 0 | 1 | 2 |
| \(P(X)\) | \(\frac{25}{36}\) | k | \(\frac{1}{36}\) |
If the mean of the random variable X is \(\frac{1}{3}\), then the variance is
Updated On: May 29, 2024
- \(\frac{1}{18}\)
- \(\frac{5}{18}\)
- \(\frac{7}{18}\)
- \(\frac{11}{18}\)
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The Correct Option is B
Solution and Explanation
The correct answer is Option (B) : \(\frac{5}{18}\)
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