Question:

\(f_{x,y}(x,y)=\begin{cases}   (x+y)       & \quad  0\le x\le 1,0\le y\le 1 \\     0  & \quad \text{otherwise }   \end{cases}\)
The Probability \(P(x+y\le1)\) is:

Updated On: Aug 20, 2024
  • \(\frac{2}{3}\)
  • \(\frac{1}{3}\)
  • \(\frac{1}{6}\)
  • \(\frac{1}{2}\)
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The Correct Option is B

Solution and Explanation

The correct option is(B): \(\frac{1}{3}\)
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