
The correct answer is (D): 1.80 hours
Explanation:
\(\frac{dA }{dt }\)- (-λ1A) + ( -λ2A)
⇒ \(\frac{dA }{dt }\) = - ( λ1 + λ2 )A
⇒ λeff = λ1 + λ2
⇒ \(\frac{ln2}{(t_{1/2})eff }\) = \(\frac{ln2}{(t_{1/2})_1}\) + \(\frac{ln2}{(t_{1/2})_2}\)
⇒ \(( t_{1/2} )\)eff =\(\frac{ 4.5 × 3 }{7.5}\) hours
= 1.8 hours
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