The correct answer is (D): 1.80 hours
Explanation:
\(\frac{dA }{dt }\)- (-λ1A) + ( -λ2A)
⇒ \(\frac{dA }{dt }\) = - ( λ1 + λ2 )A
⇒ λeff = λ1 + λ2
⇒ \(\frac{ln2}{(t_{1/2})eff }\) = \(\frac{ln2}{(t_{1/2})_1}\) + \(\frac{ln2}{(t_{1/2})_2}\)
⇒ \(( t_{1/2} )\)eff =\(\frac{ 4.5 × 3 }{7.5}\) hours
= 1.8 hours
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to:
In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.
Read More: Nuclei