Question:
A police jeep is chasing with velocity of $45\, km/h$ a thief in another jeep moving with velocity $153\,km/h$. Police fires a bullet with muzzle velocity of $180\,m/s$ The velocity it will strike the car of the thief is:
A police jeep is chasing with velocity of $45\, km/h$ a thief in another jeep moving with velocity $153\,km/h$. Police fires a bullet with muzzle velocity of $180\,m/s$ The velocity it will strike the car of the thief is:
Updated On: Jun 7, 2022
- 150 m/s
- 27 m/s
- 450 m/s
- 250 m/s
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The Correct Option is A
Solution and Explanation
Here we calculate the relative velocity of Jeep
$=153-45=108 \,km / h $
$=108 \times \frac{5}{18}=30\, m / s$
Therefore, striking speed $=$ relative speed of bullet with respect to thiefs car
$=180-30=150\, m / s$
$=153-45=108 \,km / h $
$=108 \times \frac{5}{18}=30\, m / s$
Therefore, striking speed $=$ relative speed of bullet with respect to thiefs car
$=180-30=150\, m / s$
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Concepts Used:
Motion in a Plane
It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions.
Equations of Plane Motion
The equations of motion in a straight line are:
v=u+at
s=ut+½ at2
v2-u2=2as
Where,
- v = final velocity of the particle
- u = initial velocity of the particle
- s = displacement of the particle
- a = acceleration of the particle
- t = the time interval in which the particle is in consideration