Question:

A person observes two moving trains, ‘A’ reaching the station and ‘B’ leaving the station with equal speed of 30 m/s. If both trains emit sounds with frequency 300 Hz, (Speed of sound: 330 m/s) approximate difference of frequencies heard by the person will be:

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For Doppler Effect calculations:

  • Use \[ f' = f \frac{v \pm v_o}{v \mp v_s}, \] where \(v\) is the speed of sound, \(v_o\) is the observer speed, and \(v_s\) is the source speed.
  • Add velocities for approaching sources, and subtract for receding sources.
Updated On: Mar 19, 2025
  • 33 Hz
  • 10 Hz
  • 55 Hz
  • 80 Hz
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The Correct Option is C

Solution and Explanation

Frequency Observed (Doppler Effect):

  • The observed frequency for train A (approaching):
  • The observed frequency for train B (receding):

Difference in Frequencies:

Final Answer: \(\boxed{55 \, \text{Hz}}\)

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