Question

A pendulum with a period of 2 seconds at sea level has its length doubled. Its new period is now most nearly:

• A. 1 s
• B. 2 s
• C. 4 s
• D. 5 s

Hint:

The period of a pendulum is proportional to the square root of its length.

Answer 1

The Correct Option is B

The period of a simple pendulum is given by: \[ T = 2\pi \sqrt{\frac{L}{g}} \] where: $L$ is the length of the pendulum, and $g$ is the acceleration due to gravity. If the length is doubled, the period increases by a factor of $\sqrt{2}$, so the new period will be $2 \, \text{s}$.