A member of the Lanthanoid series which is well known to exhibit +4 oxidation state is
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Cerium is the only element in the lanthanoid series that exhibits a stable +4 oxidation state, commonly in compounds like cerium dioxide (\( \text{CeO}_2 \)).
The lanthanoid series consists of the elements with atomic numbers from 57 to 71. The +4 oxidation state is relatively rare among the lanthanoids, but it is most commonly exhibited by Cerium (Ce). Cerium has an oxidation state of +4 in certain compounds, whereas other lanthanoids like Europium and Samarium predominantly show +3 oxidation states.
Thus, the correct answer is:
\[
\text{(3) Cerium}
\]
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