Question

A ketone ‘X’ gives CH\(_3\) when reacted with NaOI. The product of X on reaction with NaBH\(_4\) followed by treatment with H\(_2\)O is:

• A.
• B.
• C.
• D.

Hint:

The reaction of a ketone with NaOI gives an alkyl iodide. On reduction with NaBH\(_4\), the carbonyl group is reduced to a secondary alcohol.

Answer 1

The Correct Option is C

When ketone ‘X’ reacts with NaOI, it forms an alkyl iodide that gives a methyl group. On further reduction with NaBH\(_4\), the carbonyl group is reduced to a secondary alcohol. Hence, the product is \( {C}_6{H}_5{CH}_3{OH} \).