Question:
A junction diode has a resistance of 25 O when forward biased and 2500 O when reverse biased. The current in the diode, for the arrangement shown will be
A junction diode has a resistance of 25 O when forward biased and 2500 O when reverse biased. The current in the diode, for the arrangement shown will be
Updated On: Apr 27, 2024
- $\frac{1}{15}A$
- $\frac{1}{7}A$
- $\frac{1}{25}A$
- $\frac{1}{180}A$
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The Correct Option is B
Solution and Explanation
The junction diode is forward biased. Therefore, the effective resistance
$=25+10=35\, \Omega$
$\therefore$ Current in diode $I=\frac{5\, V }{35\, \Omega}=\frac{1}{7} A$
$=25+10=35\, \Omega$
$\therefore$ Current in diode $I=\frac{5\, V }{35\, \Omega}=\frac{1}{7} A$
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Concepts Used:
P-n Junction
A P-N junction is an interface or a boundary between two semiconductor material types, namely the p-type and the n-type, inside a semiconductor.
Biasing conditions for the p-n Junction Diode:
in p-n junction diode two operating regions are there:
- P-type
- N-type
There are three biasing conditions for p-n junction diode are as follows:
- Zero bias: When there is no external voltage applied to the p-n junction diode.
- Forward bias: P-type is connected to positive terminal of the voltage potential while n-type is connected to the negative terminal.
- Reverse bias: P-type is connected to negative terminal of the voltage potential while n-type is connected to the positive terminal.