Let \( f(x) = -3x^2(1 - x) - 3x(1 - x)^2 - (1 - x)^3 \). Then, \( \frac{df(x)}{dx} = \)
Let the area of the bounded region $ \{(x, y) : 0 \leq 9x \leq y^2, y \geq 3x - 6 \ be $ A $. Then 6A is equal to:
(b) Order of the differential equation: $ 5x^3 \frac{d^3y}{dx^3} - 3\left(\frac{dy}{dx}\right)^2 + \left(\frac{d^2y}{dx^2}\right)^4 + y = 0 $