Question

A hypothetical electromagnetic wave is show below.

The frequency of the wave is x × 10¹⁹ Hz. x = ______ (nearest integer)

Answer 1

Correct Answer: 5

Given:
\[\lambda = 1.5 \times 4 \, \text{pm} = 6 \times 10^{-12} \, \text{meter}.\]
Using the relationship:
\[\lambda \nu = c,\]
where $c = 3 \times 10^8 \, \text{m/s}$, we can find $\nu$ as:
\[6 \times 10^{-12} \cdot \nu = 3 \times 10^8\]
\[\nu = \frac{3 \times 10^8}{6 \times 10^{-12}} = 5 \times 10^{19} \, \text{Hz}.\]
Therefore, $x = 5$.