Solution: Using the principle of inclusion-exclusion for three sets \( M \), \( P \), and \( C \), we have:
\[ |M \cup P \cup C| = |M| + |P| + |C| - |M \cap P| - |P \cap C| - |M \cap C| + |M \cap P \cap C| \]
Given:
Since \(|M \cup P \cup C| = 40\), substitute the values and solve for \(|M \cap P \cap C|\):
\[ 40 = 20 + 25 + 16 - 11 - 15 - 10 + x \]
\[ x = 10 \]
Thus, the maximum number of students who passed in all three subjects is 10.
If \[ f(x) = \int \frac{1}{x^{1/4} (1 + x^{1/4})} \, dx, \quad f(0) = -6 \], then f(1) is equal to:
The term independent of $ x $ in the expansion of $$ \left( \frac{x + 1}{x^{3/2} + 1 - \sqrt{x}} \cdot \frac{x + 1}{x - \sqrt{x}} \right)^{10} $$ for $ x>1 $ is: