Question:
A girl travels along a straight line, from point A to B at a constant speed, $V_1$ meters/sec for T seconds. Next, she travels from point B to C along a straight line, at a constant speed of $V_2$ meters/sec for another T seconds. BC makes an angle 105° with AB. If CA makes an angle 30° with BC, how much time will she take to travel back from point C to A at a constant speed of $V_2$ meters/sec, if she travels along a straight line from C to A?
A girl travels along a straight line, from point A to B at a constant speed, $V_1$ meters/sec for T seconds. Next, she travels from point B to C along a straight line, at a constant speed of $V_2$ meters/sec for another T seconds. BC makes an angle 105° with AB. If CA makes an angle 30° with BC, how much time will she take to travel back from point C to A at a constant speed of $V_2$ meters/sec, if she travels along a straight line from C to A?
Updated On: Aug 9, 2024
- 0.5(√3 – 1)T
- T
- 0.5(√3 + 1)T
- √3T
- None of the above
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The Correct Option is C
Solution and Explanation
The correct option is (C) : 0.5(√3 + 1)T
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