Question:
A furnace uses 1000 kJ of fuel energy.
Useful heat output = 700 kJ.
What is the furnace efficiency?
A furnace uses 1000 kJ of fuel energy.
Useful heat output = 700 kJ.
What is the furnace efficiency?
Useful heat output = 700 kJ.
What is the furnace efficiency?
Show Hint
To calculate efficiency, always divide the useful energy output by the total energy input and multiply by 100 to get the percentage.
Updated On: Jun 19, 2025
- 50%
- 70%
- 80%
- 30%
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The Correct Option is B
Solution and Explanation
Efficiency (η) is calculated using the formula:
η = (Useful heat output / Total energy input) × 100
Given:
- Total energy input = 1000 kJ
- Useful heat output = 700 kJ
Substituting the values:
η = (700 / 1000) × 100 = 70%
Thus, the furnace efficiency is 70%.
η = (Useful heat output / Total energy input) × 100
Given:
- Total energy input = 1000 kJ
- Useful heat output = 700 kJ
Substituting the values:
η = (700 / 1000) × 100 = 70%
Thus, the furnace efficiency is 70%.
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