The refractive index helps relate apparent and actual velocities when observations are made across media boundaries. Always apply the refractive index in the correct direction (water to air or vice versa).
When light (or observation) passes from water to air, the apparent velocity of the bird as seen by the fish is related to the actual velocity of the bird by the refractive index \( \mu \). The relationship is given as: \[ v_{\text{actual}} = \mu \times v_{\text{apparent}}. \]
Here:
Substitute the values: \[ v_{\text{actual}} = \frac{4}{3} \times 12 = 16 \, \text{ms}^{-1}. \]
Let \( a \in \mathbb{R} \) and \( A \) be a matrix of order \( 3 \times 3 \) such that \( \det(A) = -4 \) and \[ A + I = \begin{bmatrix} 1 & a & 1 \\ 2 & 1 & 0 \\ a & 1 & 2 \end{bmatrix} \] where \( I \) is the identity matrix of order \( 3 \times 3 \).
If \( \det\left( (a + 1) \cdot \text{adj}\left( (a - 1) A \right) \right) \) is \( 2^m 3^n \), \( m, n \in \{ 0, 1, 2, \dots, 20 \} \), then \( m + n \) is equal to:
Rate law for a reaction between $A$ and $B$ is given by $\mathrm{R}=\mathrm{k}[\mathrm{A}]^{\mathrm{n}}[\mathrm{B}]^{\mathrm{m}}$. If concentration of A is doubled and concentration of B is halved from their initial value, the ratio of new rate of reaction to the initial rate of reaction $\left(\frac{\mathrm{r}_{2}}{\mathrm{r}_{1}}\right)$ is