A die is thrown once. If E represents the event ‘the number obtained on the die is a multiple of 3’ and F represents the event ‘the number obtained on the die is even’, then tell whether the events E and F are independent.
Step 1: We calculate \( P(E) \), \( P(F) \), and \( P(E \cap F) \): - \( E = \{3, 6\} \), so \( P(E) = \frac{2}{6} = \frac{1}{3} \) - \( F = \{2, 4, 6\} \), so \( P(F) = \frac{3}{6} = \frac{1}{2} \) - \( E \cap F = \{6\} \), so \( P(E \cap F) = \frac{1}{6} \)
Step 2: Check if the events are independent: For independent events, \( P(E \cap F) = P(E) \cdot P(F) \). \[ P(E) \cdot P(F) = \frac{1}{3} \times \frac{1}{2} = \frac{1}{6} \] Since \( P(E \cap F) = \frac{1}{6} \), the events \( E \) and \( F \) are independent.
(b) Order of the differential equation: $ 5x^3 \frac{d^3y}{dx^3} - 3\left(\frac{dy}{dx}\right)^2 + \left(\frac{d^2y}{dx^2}\right)^4 + y = 0 $