A die is thrown once. If E represents the event ‘the number obtained on the die is a multiple of 3’ and F represents the event ‘the number obtained on the die is even’, then tell whether the events E and F are independent.
Step 1: We calculate \( P(E) \), \( P(F) \), and \( P(E \cap F) \): - \( E = \{3, 6\} \), so \( P(E) = \frac{2}{6} = \frac{1}{3} \) - \( F = \{2, 4, 6\} \), so \( P(F) = \frac{3}{6} = \frac{1}{2} \) - \( E \cap F = \{6\} \), so \( P(E \cap F) = \frac{1}{6} \)
Step 2: Check if the events are independent: For independent events, \( P(E \cap F) = P(E) \cdot P(F) \). \[ P(E) \cdot P(F) = \frac{1}{3} \times \frac{1}{2} = \frac{1}{6} \] Since \( P(E \cap F) = \frac{1}{6} \), the events \( E \) and \( F \) are independent.
Let the mean and variance of 7 observations 2, 4, 10, x, 12, 14, y, where x>y, be 8 and 16 respectively. Two numbers are chosen from \(\{1, 2, 3, x-4, y, 5\}\) one after another without replacement, then the probability, that the smaller number among the two chosen numbers is less than 4, is:
If the mean and the variance of the data 
are $\mu$ and 19 respectively, then the value of $\lambda + \mu$ is