Current density \( \mathbf{j} \) is the current per unit area and is a vector. It is given by:
\[ \mathbf{j} = \frac{I}{A} \]
The drift velocity \( v_d \) is related to the electric field \( E \) as:
\[ v_d = -\frac{eE\tau}{m} \]
Where \( e \) is the charge of an electron, \( \tau \) is the relaxation time, and \( m \) is the mass of the electron.
The current density is given by the product of the number of charge carriers \( n \), the charge of the carriers \( e \), and their drift velocity \( v_d \):
\[ \mathbf{j} = n(-e)v_d = n \cdot (-e) \cdot \left( -\frac{eE\tau}{m} \right) \]
Simplifying this, we get:
\[ \mathbf{j} = \frac{ne^2\tau E}{m} \]
Thus, the conductivity \( \alpha \) is:
\[ \alpha = \frac{ne^2\tau}{m} \]
The Wheatstone bridge is used to measure an unknown resistance. It is balanced when the following condition is met:
\[ \frac{R_1}{R_2} = \frac{R_3}{R_4} \]
In this case, there is no current flowing through the galvanometer, and the bridge is considered balanced.

The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
A Wheatstone bridge is initially at room temperature and all arms of the bridge have same value of resistances \[ (R_1=R_2=R_3=R_4). \] When \(R_3\) resistance is heated, its resistance value increases by \(10%\). The potential difference \((V_a-V_b)\) after \(R_3\) is heated is _______ V. 
If vector \( \mathbf{a} = 3 \hat{i} + 2 \hat{j} - \hat{k} \) \text{ and } \( \mathbf{b} = \hat{i} - \hat{j} + \hat{k} \), then which of the following is correct?