Question

A cyclic process involves 3 states with 1 mole of ideal gas as follows:\ State 1: \( T = 300 \text{ K},\ P = 15 \text{ bar} \)\ State 2: \( T = 300 \text{ K},\ P = 10 \text{ bar} \)\ State 3: \( T = 300 \text{ K},\ P = 5 \text{ bar} \)\ Calculate the total work done during one complete cycle.

• A. \( \frac{25}{3} \ \text{L bar} \)
• B. \( -\frac{25}{3} \ \text{L bar} \)
• C. \( \frac{50}{3} \ \text{L bar} \)
• D. \( -\frac{50}{3} \ \text{L bar} \)

Hint:

In cyclic PV graphs, total work done = area enclosed by the cycle.

Answer 1

The Correct Option is C

This is a cyclic process with constant temperature (isothermal) and ideal gas. The area under the process graph (P-V) gives work done. \ As the pressure reduces from 15 bar to 5 bar through 3 steps and returns to original, total work is equal to the area enclosed — \( \frac{50}{3} \) L bar.