
The solution is already infinitely dilute, meaning the molar conductivity is at its maximum value. Adding more water will not dilute the solution further; therefore, there will be no change in molar conductivity. It will remain the same.
\[\text{Molar conductivity } (\Lambda_m) \propto \frac{\kappa}{c}\]
where $\kappa$ is the conductivity and $c$ is the concentration. For infinitely dilute solutions, $c$ is already approaching zero, and $\Lambda_m$ becomes constant.

If the molar conductivity ($\Lambda_m$) of a 0.050 mol $L^{–1}$ solution of a monobasic weak acid is 90 S $cm^{2} mol^{–1}$, its extent (degree) of dissociation will be:
[Assume: $\Lambda^0$ = 349.6 S $cm^{2} mol^{–1}$ and $\Lambda^0_{\text{acid}}$ = 50.4 S$ cm^{2} mol^{–1}$]
In the circuit shown, assuming the threshold voltage of the diode is negligibly small, then the voltage \( V_{AB} \) is correctly represented by: