Question:
A conducting square loop of side L and resistance R moves in its plane with a uniform velocity v, perpendicular to one of its sides. A magnetic field of induction B, constant in space and time and pointing perpendicularly into the plane of the square, exists everywhere in space. The current induced in the loop is
A conducting square loop of side L and resistance R moves in its plane with a uniform velocity v, perpendicular to one of its sides. A magnetic field of induction B, constant in space and time and pointing perpendicularly into the plane of the square, exists everywhere in space. The current induced in the loop is
Updated On: Jul 27, 2022
- BLv/R in the clockwise direction
- BLv/R in the anticlockwise direction
- 2 BLv/R in the clockwise direction
- zero
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The Correct Option is D
Solution and Explanation
From Faraday's law of electromagnetic induction, emf is induced with changing magnetic flux, but in this case since, magnetic field is pointing perpendicularly hence, magnetic flux does not change, hence current in the loop is zero.
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Concepts Used:
Faradays Laws of Induction
There are two laws, given by Faraday which explain the phenomena of electromagnetic induction:
Faraday's First Law:
Whenever a conductor is placed in a varying magnetic field, an emf is induced. If the conductor circuit is closed, a current is induced, known as the induced current.
Faraday's Second Law:
The Emf induced inside a coil is equal to the rate of change of associated magnetic flux.
This law can be mathematically written as:
∈\(-N {\triangle \phi \over \triangle t}\)
