Question:

A conducting circular loop of radius $\frac{10}{\sqrt{\pi}} cm$ is placed perpendicular to a uniform magnetic field of $0.5 T$ The magnetic field is decreased to zero in $0.5 s$ at a steady rate The induced emf in the circular loop at $0.25 s$ is:

Updated On: Mar 19, 2025
  • $emf =1 mV$
  • $emf =100 mV$
  • $emf =5 mV$
  • $emf =10 mV$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

The area of the loop is: \[ A = \pi r^2 = \pi \left(\frac{10}{\sqrt{\pi}}\right)^2 = 100 \, \text{cm}^2 = 10^{-2} \, \text{m}^2. \] The magnetic flux through the loop is: \[ \Phi = B \cdot A = 0.5 \cdot 10^{-2} = 5 \cdot 10^{-3} \, \text{Wb}. \] The emf induced is: \[ \mathcal{E} = \left| \frac{\Delta \Phi}{\Delta t} \right| = \frac{5 \cdot 10^{-3}}{0.5} = 10 \, \text{mV}. \]
Was this answer helpful?
6
19

Top Questions on Electromagnetic induction

View More Questions

Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter