Question:

A conducting circular loop is placed in a uniform magnetic field, $B = 0.025\, T$ with its plane perpendicular to the loop. The radius of the loop is made to shrink at a constant rate of $1 \,mm \,s^{-1}$. The induced emf when the radius is $2 \,cm$, is

Updated On: Jul 5, 2022
  • $2\pi \, \mu V$
  • $\pi \,\mu V$
  • $\frac{\pi}{2}\,\mu V$
  • $2\, \mu V$
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The Correct Option is B

Solution and Explanation

Here, Magnetic field, $B=0.025\,T$ Radius of the loop, $r=2\, cm=2\times10^{-2}\, m$ Constant rate at which radius of the loop shrinks, $\frac{d r}{d t}=1\times10^{-3}\,m\,s^{-1}$ Magnetic flux linked with the loop is $\phi=BA\, cos\theta =B \left(\pi r^{2}\right)cos0^{\circ}=B\pi r^{2}$ The magnitude of the induced emf is $\left|\varepsilon\right|=\frac{d \phi}{d t}=\frac{d}{d t}\left(B\pi r^{2}\right)=B\pi2r \frac{dr}{d t}$ $=0.025\times\pi\times2\times2\times10^{-2}\times1\times10^{-3}$ $=\pi\times10^{-6}\, V =\pi\,\mu V$
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Concepts Used:

Faradays Laws of Induction

There are two laws, given by Faraday which explain the phenomena of electromagnetic induction:

Faraday's First Law:

Whenever a conductor is placed in a varying magnetic field, an emf is induced. If the conductor circuit is closed, a current is induced, known as the induced current.

Faraday's Second Law:

The Emf induced inside a coil is equal to the rate of change of associated magnetic flux.

This law can be mathematically written as:

\(-N {\triangle \phi \over \triangle t}\)