A concave mirror forms an image at twice its focal length, a scenario where we need to analyze the image characteristics using a lens/mirror equation. For a mirror, this equation is:
1/f = 1/v + 1/u
Where:
Given that the image distance v is twice the focal length, i.e., v = 2f. Substituting in the lens/mirror equation:
1/f = 1/(2f) + 1/u
Simplifying, we get:
1/u = 1/f - 1/(2f) = (2-1)/(2f) = 1/(2f)
Thus, u = 2f. This indicates that the object is also placed at twice the focal length. In this case, the object is at the center of curvature.
For a concave mirror, when the object is placed at the center of curvature, several characteristics of the image are observed:
Thus, the correct answer is: Real, inverted, same size.
Match List-I with List-II for the index of refraction for yellow light of sodium (589 nm)
LIST-I (Materials) | LIST-II (Refractive Indices) | ||
---|---|---|---|
A. | Ice | I. | 1.309 |
B. | Rock salt (NaCl) | II. | 1.460 |
C. | CCl₄ | III. | 1.544 |
D. | Diamond | IV. | 2.417 |
Choose the correct answer from the options given below:
Match the LIST-I with LIST-II
LIST-I | LIST-II | ||
---|---|---|---|
A. | Compton Effect | IV. | Scattering |
B. | Colors in thin film | II. | Interference |
C. | Double Refraction | III. | Polarization |
D. | Bragg's Equation | I. | Diffraction |
Choose the correct answer from the options given below: