Question:
A compound of formula $A_2B_3$ has the hcp lattice. Which atom forms the hcp lattice and what fraction of tetrahedral voids is occupied by the other atoms :
A compound of formula $A_2B_3$ has the hcp lattice. Which atom forms the hcp lattice and what fraction of tetrahedral voids is occupied by the other atoms :
Updated On: Jul 15, 2024
- hcp lattice-A, $\frac{2}{3}$ Tetrachedral voids-B
- hcp lattice-B, $\frac{1}{3}$ Tetrachedral voids-A
- hcp lattice-B, $\frac{2}{3}$ Tetrachedral voids-A
- hcp lattice-A, $\frac{1}{3}$ Tetrachedral voids-B
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The Correct Option is B
Solution and Explanation
$A_2B_3$ has HCP lattice
If $A$ form HCP, then $\frac{3^{th}}{4}$ of THV must occupied by B to form $A_2B_3$ .
If $B$ form HCP, then $\frac{1^{th}}{3}$ of THV must occupied by A to form $A_2B_3$
If $A$ form HCP, then $\frac{3^{th}}{4}$ of THV must occupied by B to form $A_2B_3$ .
If $B$ form HCP, then $\frac{1^{th}}{3}$ of THV must occupied by A to form $A_2B_3$
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Concepts Used:
Solid State
Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions.
Types of Solids:
Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;
- Amorphous solids behave the same as super cool liquids due to the arrangement of constituent particles in short-range order. They are isotropic and have a broad melting point (range is about greater than 5°C).
- Crystalline solids have a fixed shape and the constituent particles are arranged in a long-range order.