A metal crystallizes in simple cubic lattice. The volume of one unit cell is \( 6.4 \times 10^{-7} \, \text{pm}^3 \). What is the radius of the metal atom in pm?
Show Hint
In simple cubic lattices, the edge length of the unit cell is twice the radius of the atoms. Use this to relate volume and atomic radius.
For a simple cubic lattice, the relationship between the unit cell volume \( V_{\text{unit}} \) and the atomic radius \( r \) is:
\[
V_{\text{unit}} = (2r)^3
\]
Given that the volume is \( 6.4 \times 10^{-7} \, \text{pm}^3 \), solving for \( r \) gives us a radius of 200 pm.