To find the velocity of sound using the given problem, we'll utilize the principles of sound waves in organ pipes. Since both pipes are in fundamental modes, we'll use the fundamental frequency formulas for open and closed pipes.
The calculated velocity of sound \(v = 294 \, \text{m/s}\) is within the specified range (294, 294).
For a closed pipe of length \(L = 150 \, \text{cm} = 1.5 \, \text{m}\):
The fundamental frequency is given by:
\(f_c = \frac{v}{4L}.\)
For an open pipe of length \(L = 350 \, \text{cm} = 3.5 \, \text{m}\):
The fundamental frequency is given by:
\(f_o = \frac{v}{2L}.\)
Given that the beat frequency is:
\(|f_c - f_o| = 7 \, \text{Hz}.\)
Substituting:
\(\left| \frac{v}{4 \cdot 1.5} - \frac{v}{2 \cdot 3.5} \right| = 7.\)
Simplifying:
\(\left| \frac{v}{6} - \frac{v}{7} \right| = 7.\)
Solving for \(v\):
\(\frac{v}{42} = 7 \implies v = 42 \cdot 7 = 294 \, \text{m/s}.\)
The Correct answer is: 294
Two plane polarized light waves combine at a certain point, whose "E" components are: \[ E_1 = E_0 \sin \omega t, \quad E_2 = E_0 \sin \left( \omega t + \frac{\pi}{3} \right) \] Find the amplitude of the resultant wave.
Let one focus of the hyperbola \( H : \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 \) be at \( (\sqrt{10}, 0) \) and the corresponding directrix be \( x = \dfrac{9}{\sqrt{10}} \). If \( e \) and \( l \) respectively are the eccentricity and the length of the latus rectum of \( H \), then \( 9 \left(e^2 + l \right) \) is equal to:
