Question

A circus artist is climbing a \(20\, m\) long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is \(30 °\).

Answer 1

It can be observed from the figure that AB is the pole.
In ∆ABC,

\(\frac{AB}{AC} = Sin 30^{\degree}\)

\(\frac{AB}{20} = \frac{1}2\)

\(AB = \frac{20}2 = 10\)

Therefore, the height of the pole is \(10\, m\).