Question

A certain transistor is to be operated with \( V_{CE} = 6V \). If its maximum power rating is 250 mW, what is the maximum collector current that it can handle?

• A. \( 1.5 \) mA
• B. \( 1.5 \) A
• C. \( 41.7 \) mA
• D. \( 4.17 \) A

Answer 1

The Correct Option is C

The maximum power rating of the transistor can be expressed as the product of the collector current \( I_C \) and the collector-emitter voltage \( V_{CE} \), i.e.:

\(P_{\text{max}} = V_{CE} \times I_C \)

We are given the following values:

• Maximum power rating \( P_{\text{max}} = 250 \, \text{mW} = 0.250 \, \text{W} \)
• Collector-emitter voltage \( V_{CE} = 6 \, \text{V} \)

Now, we can rearrange the equation to solve for the maximum collector current \( I_C \):

\(I_C = \frac{P_{\text{max}}}{V_{CE}}\)

Substitute the given values into the equation:

\(I_C = \frac{0.250}{6} \approx 0.0417 \, \text{A} = 41.7 \, \text{mA}\)

Conclusion: The maximum collector current that the transistor can handle is \( 41.7 \, \text{mA} \).