Question

A capacitor of capacitance C=900 pF is charged rally by 100 V battery B as shown in figure (a). Then B is disconnected from the battery and connected to another uncharged capacitor of capacitance C=900 pF as shown in figure (b). The electrostatic energy stored by the system (b)is:

• A. \(4.5 \times 10^{-6} J\)
• B. \(3.25 \times 10^{-6} J\)
• C. \(2.25 \times 10^{-6} J\)
• D. \(1.5 \times 10^{-6} J\)

Answer 1

The Correct Option is C

The correct option is (C): \(2.25 \times 10^{-6} J\)