Question:
A body projected vertically upwards with a velocity u returns to the starting point in $4 s$. If $g = 10 \,m s^{-2}$, the value of $u$ in $m/s$ is
A body projected vertically upwards with a velocity u returns to the starting point in $4 s$. If $g = 10 \,m s^{-2}$, the value of $u$ in $m/s$ is
Updated On: May 27, 2022
- 10
- 5
- 4
- 20
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The Correct Option is D
Solution and Explanation
Time of ascent = Time of descent = $\frac{4}{2} $ = 2 s
$\nu $ u + (-gt) i.e. 0 = u - 10 $\times$ 2 i.e. u = 20 m $s^{-1}$
$\nu $ u + (-gt) i.e. 0 = u - 10 $\times$ 2 i.e. u = 20 m $s^{-1}$
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.