Question:
Updated On: Apr 26, 2024
- (A) 0
- (B) -1
- (C) 1
- (D) 2
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Explanation:
c1 → c1 + c2 + c3
c1 → c1 + c2 + c3
Was this answer helpful?
0
0
Top Questions on Area between Two Curves
- The area of the region enclosed by the curves \( y = x^2 - 4x + 4 \) and \( y^2 = 16 - 8x \) is:
- JEE Main - 2025
- Mathematics
- Area between Two Curves
- The area of the region enclosed by the curves \( y = x^2 - 4x + 4 \) and \( y^2 = 16 - 8x \) is:
- JEE Main - 2025
- Mathematics
- Area between Two Curves
- The area of the region \[ \{ (x, y) : x^2 + 4x + 2 \leq y \leq |x| + 2 \} \] is equal to:
- JEE Main - 2025
- Mathematics
- Area between Two Curves
- Let $A$ be the area of the region
$\left\{(x, y): y \geq x^2, y \geq(1-x)^2, y \leq 2 x(1-x)\right\}$.
Then $540 A$ is equal to ______.- JEE Main - 2025
- Mathematics
- Area between Two Curves
- The area of the region bounded by the line $y = x$ and the curve $y = x^3$ is:
- KCET - 2024
- Mathematics
- Area between Two Curves
View More Questions
Questions Asked in WBJEE exam
- Let \(f : \mathbb{R} \to \mathbb{R}\) be given by \(f(x) = |x^2 - 1|\), then:
- \(f(x) = \cos x - 1 + \frac{x^2}{2!}, \, x \in \mathbb{R}\)
Then \(f(x)\) is: - Let \(f : \mathbb{R} \to \mathbb{R}\) be a differentiable function and \(f(1) = 4\). Then the value of
\[ \lim_{x \to 1} \int_{4}^{f(x)} \frac{2t}{x - 1} \, dt \]- WBJEE - 2024
- Integration
- If \(\int \frac{\log(x + \sqrt{1 + x^2})}{1 + x^2} \, dx = f(g(x)) + c\), then:
- WBJEE - 2024
- Integration
- The equation \(2x^5 + 5x = 3x^3 + 4x^4\) has:
- WBJEE - 2024
- Quadratic Equation
View More Questions