A 2V cell is connected across the points A and B as shown in the figure. Assume that the resistance of each diode is zero in forward bias and infinity in reverse bias. The current supplied by the cell is:
Step 1: In this circuit, the diodes act as ideal diodes, which means they conduct when forward-biased and do not conduct when reverse-biased.
Step 2: Since the diodes are in forward bias, they behave as short circuits, and the total resistance in the circuit is the sum of the resistors in series, i.e.,
\( R_{\text{total}} = 10 \, \Omega + 20 \, \Omega = 30 \, \Omega. \)
Step 3: Using Ohm's law, \( V = IR \), the current supplied by the cell is:
\[ I = \frac{V}{R} = \frac{2 \, \text{V}}{30 \, \Omega} = 0.0667 \, \text{A} \approx 0.2 \, \text{A}. \]
A 2V cell is connected across points A and B in a circuit containing two ideal diodes and two resistors. The diodes have zero resistance in forward bias and infinite resistance in reverse bias.
Circuit Analysis:
Equivalent Circuit:
The circuit simplifies to the 2V cell connected in series with only the 10Ω resistor from the top branch. The bottom branch is inactive due to the reverse-biased diode.
I= 0.2A
Two cells of emf 1V and 2V and internal resistance 2 \( \Omega \) and 1 \( \Omega \), respectively, are connected in series with an external resistance of 6 \( \Omega \). The total current in the circuit is \( I_1 \). Now the same two cells in parallel configuration are connected to the same external resistance. In this case, the total current drawn is \( I_2 \). The value of \( \left( \frac{I_1}{I_2} \right) \) is \( \frac{x}{3} \). The value of x is 1cm.
Current passing through a wire as function of time is given as $I(t)=0.02 \mathrm{t}+0.01 \mathrm{~A}$. The charge that will flow through the wire from $t=1 \mathrm{~s}$ to $\mathrm{t}=2 \mathrm{~s}$ is:
In the figure shown below, a resistance of 150.4 $ \Omega $ is connected in series to an ammeter A of resistance 240 $ \Omega $. A shunt resistance of 10 $ \Omega $ is connected in parallel with the ammeter. The reading of the ammeter is ______ mA.