
Formulas for motional emf \((E = Blv)\) and the force on a current carrying conductor in a magnetic field \((F = BIl)\). Make sure your units are con sistent
The force on a conductor in a magnetic field is given by:
\( F = I \ell B \)
Where:
The current \( I \) can be expressed as:
\( I = \frac{e}{R} \)
Substitute \( I \) into the force equation:
\[ F = Bv \ell B \cdot \frac{\ell}{R} \]
Simplify:
\[ F = \frac{B^2 \ell^2 v}{R} \]
Given:
Substitute these values into the equation:
\[ F = \frac{(15)^2 \cdot (1)^2 \cdot 4}{5} \]
Simplify:
\[ F = \frac{225 \cdot 4}{5} = 180 \, \text{N} \]
The magnetic force is \( F = 18 \, \text{N}. \)
A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field \( B \) exists into the page. The bar starts to move from the vertex at time \( t = 0 \) with a constant velocity. If the induced EMF is \( E \propto t^n \), then the value of \( n \) is _____. 
A thin uniform rod (\(X\)) of mass \(M\) and length \(L\) is pivoted at a height \( \left(\dfrac{L}{3}\right) \) as shown in the figure. The rod is allowed to fall from a vertical position and lie horizontally on the table. The angular velocity of this rod when it hits the table top is ________. (\(g\) = gravitational acceleration) 
If $\cot x=\dfrac{5}{12}$ for some $x\in(\pi,\tfrac{3\pi}{2})$, then \[ \sin 7x\left(\cos \frac{13x}{2}+\sin \frac{13x}{2}\right) +\cos 7x\left(\cos \frac{13x}{2}-\sin \frac{13x}{2}\right) \] is equal to